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7v^2+6v-16=0
a = 7; b = 6; c = -16;
Δ = b2-4ac
Δ = 62-4·7·(-16)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-22}{2*7}=\frac{-28}{14} =-2 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+22}{2*7}=\frac{16}{14} =1+1/7 $
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